gh-145552: smtplib: quoteaddr() returns malformed address for input '<'#145553
gh-145552: smtplib: quoteaddr() returns malformed address for input '<'#145553stefanzetzsche wants to merge 10 commits intopython:mainfrom
quoteaddr() returns malformed address for input '<'#145553Conversation
Input starting with '<' but missing closing '>' was returned verbatim. Ensure the result always ends with '>'.
Add testQuoteAddr for basic quoteaddr behavior and testQuoteAddrMalformedAngleBracket for inputs starting with '<' but missing closing '>'. The latter fails without the fix.
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…stefanzetzsche/cpython into fix/smtplib_quoteaddr_malformed
| # parseaddr couldn't parse it, wrap it in angle brackets. | ||
| if addrstring.strip().startswith('<'): | ||
| return addrstring | ||
| if addrstring.strip().endswith('>'): |
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Sorry for the delay in responding.
I'd prefer to do addrstring.strip() == '<>', which theoretically matches the old behavior. (I say theoretically because the code the old version of this code was calling has moved on as well and I don't feel like going down that rabbit hole.) In any case, it should be correct: only <> is a special case per RFC 5321; we otherwise don't want to do more to fix user errors than to ensure that the provided originator address is sorrounded by the angle quotes.
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Problem
quoteaddr()formats addresses for SMTPMAIL FROM:andRCPT TO:commands, which require angle-bracket format (<addr>). It first triesemail.utils.parseaddr(); when that fails (for inputs like'<','< ','@'), a fallback path checks if the input starts with<and returns it verbatim — without verifying it also ends with>.The
startswith('<')check was introduced in 4c14bba as part of #51733. Before that commit, unparseable input was unconditionally wrapped in<>.Reproducer
Why not unconditional wrapping?
Simply removing the
startswith('<')branch and always wrapping with"<%s>"would break the null sender<>, which is a valid SMTP construct (RFC 5321 bounce path).parseaddr('<>')returns('', '')— a parse failure — so unconditional wrapping would produce<<>>, which is malformed. Thestartswith('<')check exists specifically to preserve already-bracketed input thatparseaddrcan't handle.Fix
Keep the
startswith('<')check but add anendswith('>')guard. Already-bracketed input (like<>) passes through; half-open input (like<) falls through to unconditional wrapping: